 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Set A and B (Posted on 2002-05-29) Consider the following two sets:

Set A = { 2,3,4,6 }
Set B = { 2,5,7,9 }

What is the probability that two randomly chosen elements from B would add up to be more than the product of two randomly chosen elements from A?

 Submitted by Dulanjana Rating: 2.5000 (8 votes) Solution: (Hide) There are six ways to pick a pair of numbers from a set of four. For set A, the possible pairs and their products are: (2*3) = 6 (2*4) = 8 (2*6) = 12 (3*4) = 12 (3*6) = 18 (4*6) = 26 For set B, the pairs and their sums are: (2+5) = 7 (2+7) = 9 (2+9) = 11 (5+7) = 12 (5+9) = 14 (7+9) = 16 Out of the possibilities listed, the outcomes where the sum of a pair from B is greater than a product of a pair from A is as follows: Product of A is 6: Sum of B can be 7, 9, 11, 12, 14 and 16 Product of A is 8: Sum of B can be 9, 11, 12, 14 and 16 Product of A is 12 (2*6): Sum of B can be 14 and 16 Product of A is 12 (3*4): Sum of B can be 14 and 16 Product of A is 18 or 24: No pair from B will result in a greater sum. In all, we have 6+5+2+2 = 15 possibilities to meet the condition required, out of a total 36 possible outcomes. This the probability is 15/36 Subject Author Date Answer Praneeth 2007-08-23 07:13:58 answer to the problem K Sengupta 2007-03-09 05:22:12 I concur with the original Tristan 2003-04-26 11:51:46 answer maybe luvya2003 2003-03-15 10:04:46 re: AAaarrghhh! levik 2002-05-29 19:17:54 AAaarrghhh! TomM 2002-05-29 17:11:52 Brute Arithmatic TomM 2002-05-29 17:03:31 Early thoughts TomM 2002-05-29 16:47:20 Please log in:

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