All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Marriage Muse (Posted on 2013-05-03)
Four men -- Aaron, Barry, Colin & David and four women -- Marie, Norma, Olive & Pearl -- attended a wedding.
1. One of the four men married one of the four women.
2. If neither Aaron nor Marie got married, then Olive got married.
3. If neither Aaron nor Norma got married, then Barry got married.
4. If neither Barry nor Olive got married, then Colin got married.
5. If neither Colin nor Norma got married, then Marie got married.
Who got married?

 No Solution Yet Submitted by K Sengupta Rating: 2.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 A logical marriage (spoiler) | Comment 2 of 4 |
I prefer to work with the contrapositives:

(2) If not O, then A or M
(3) If not B, then A or N
(4) If not C, then B or O
(5) If not M, then C or N

Assume B is not the groom.  Then, from (3), A or N got married.
If A, then from (4) A must have married O.
But A & O contradicts 5.
If N, then from (2) N must have married A.
But N & A contradicts 4.
Therefore, our initial assumption is wrong, and B is the groom.

This satisfies (3) and (4), and the other two simplify to

(2) If not O, then M.
(5) If not M, then N.

One or both of the two predicates must be true, so the bride must be M or N.  If N is the bride, then this contradicts (2), so N is not the bride.  So M must be the bride.

Only solution: B & M were married.

Edited on May 3, 2013, 8:20 pm
 Posted by Steve Herman on 2013-05-03 19:14:36

 Search: Search body:
Forums (3)