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Rhombus Rationale (Posted on 2013-08-11) |
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Each of the two diagonals and each of the four sides of a rhombus has integer lengths, satisfying the condition: x2 + y2 = 4z2, where x, y are the length of the diagonals and z being the length of each side.
Is the area of the rhombus always divisible by 24?
If so, prove it. Otherwise provide a counter example.
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| spoiler | Ady TZIDON | 2013-08-11 10:57:44 |
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