Each letter of the alphabet has been assigned a different value from 1 to 26. The total values of the letters contained in a given word are as
given below. Determine the value assigned to each letter of the alphabet.
BEG = 59 CALL = 48 CHIEF = 36 CRAZY = 60
DEN = 53 GAME = 47 GUN = 51 HAM = 16
HAVE = 40 IF = 11 JACK = 24 KEY = 43
LAZE = 57 MAP = 28 MOVE = 58 NEON = 86
OXEN = 82 PALM = 47 QUIT = 40 QUITE = 60
STALL = 80 TALK = 39 TORE = 73 VAST = 51
WALK = 54
*** Pen and Paper solution only.
(In reply to
re: Solution by Ady TZIDON)
Detailed sequence is as follows
First from (QUIT,QUITE) E=20 and (MAP,PALM) L=19 substituting we get
BG=39,DN=33,HAV=11,AZ=18,OXN=62,STA=42,WAK=35,
CA=10,GAM=27,TAK=20,CH=5,MOV=38,TOR=53,KY=23,NON=66
Second (STA,VAST) give V=9
substituting we get HA=11, MO=29
Third (HAM,HA) gives M=5, (NON,MO) gives N=21 & O=24 and DN gives D=12 and OXN gives X=17
substituting we get GA=22,AP=23,GU=30,TR=29,
CH=5 ( options are 1 &4 or 2,3 ) since HA=11 and CA=10
so C=2, H=3 and A=8
substituting we get P=15(AP), Z= 10(AZ), G=14(GA), B=25(BG), U=16(GU), TK=12, JK=10, ST=34,WK=27,JK=14, RZY=50, QIT=24
only value of K that satisfies all letters considering remaining number is K=1,
then Y=22, T=11, W=26, J=13 and S=23, R=18, Z=10
We are left with IF=11, QI=13 so I=7, F=4 & Q=6
I hope I was clear.

Posted by Salil
on 20131204 06:08:17 