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 Area Ascertainment (Posted on 2014-02-06)
A piece of paper has the precise shape of a triangle ABC with two side lengths AB and AC being respectively 36 and 72 with ∠ABC = 90o

Find the area of the set of points P inside ΔABC such that if creases are made by folding (and then unfolding) each of A, B, C to P, then the creases do not overlap.

 No Solution Yet Submitted by K Sengupta No Rating

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By playing with Geometers' Sketchpad we can see that point P must lie within a semicircle with diameter BC and also within a semicircle with diameter AB. It also must lie within the semicircle with diameter AC, but, this, being the hypotenuse, encompasses the whole triangle.

The two important semicircles meet at B and at a point--call it D--along the hypotenuse AC, so we need to find the combined areas of two back-to-back segments of circles with endpoints B and D.

The segment with arc centered at the midpoint of BC has area pi*(18*sqrt(3))^2 / 6 - 27*9*sqrt(3).

The segment with arc centered at the midpoint of AB has area pi*18^2 / 3 - 9*9*sqrt(3).

That brings the total area to

pi*18^2*5/6 - 324*sqrt(3)

= 270*pi - 324*sqrt(3) ~= 287.045554816926

 Posted by Charlie on 2014-02-06 16:36:27

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