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Five by Five (Posted on 2013-10-21) Difficulty: 2 of 5
The Fibonacci recurrence (F1 = 1, F2 = 1 and Fn = Fn - 1 + Fn - 2) leads to an infinite sequence of numbers starting with

1, 1, 2, 3, 5,
8, 13, 21, 34, 55,
89, 144, 233, 377, 610, ...

Note that the 5th, 10th and 15th numbers are all divisible by 5.
Show that every fifth number in the sequence is divisible by 5.

No Solution Yet Submitted by Danish Ahmed Khan    
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Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: modular solutionJer2013-10-22 13:54:30
Solutionmodular solutionCharlie2013-10-21 13:05:30
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