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| Midpoint of Two Chords (Posted on 2013-09-15) |
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Let AB and BC be chords of a circle ( with
|AB| > |BC| ). Let M be the midpoint of
arc ABC and F the foot of the perpendicular
from M to AB.
Prove that |AF| = ( |AB| + |BC| )/2.
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Subject |
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Date |
 | Solution | Harry | 2013-09-20 16:51:33 |
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