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Four Digits (Posted on 2013-11-05) Difficulty: 2 of 5
You have a number where any digit appears at most twice. The sum of all neighboring four digits in this number is a square number.

What is the maximum possible value for this number?

Example: 205290 is such a number because no digit appears more than twice and 2+0+5+2, 0+5+2+9, and 5+2+9+0 are square numbers.

No Solution Yet Submitted by Danish Ahmed Khan    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts re: computer solution --- KUDOS | Comment 3 of 4 |
(In reply to computer solution by Charlie)


Truly nice puzzle and excellent solution.
I have tried to solve it p&p and apparently the computer approach is inevitable.
I have rated it 4, but must complain that the d2 was misleading.

  Posted by Ady TZIDON on 2013-11-05 14:55:08
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