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Angle Bisector (Posted on 2013-10-06) |
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Let ABC be a triangle with a, b, and c the lengths of the
sides opposite vertices A, B, and C respectively.
Let the cevian CD bisect ∠ACB.
Prove the following:
|CD|2 = ab[ 1-{c/(a+b)}2 ]
without using the Law of Cosines.
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