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Incircles in equilateral triangles (Posted on 2014-01-18) |
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In an equilateral triangle ABC the lines AC'A', BA'B', CB'C' are drawn making equal angles with AB, BC, CA, respectively, forming the triangle A'B'C', and so that the radius of the incircle of triangle A'B'C' is equal to the radius of the incircle of triangle AA'B. Find A'B' in terms of AB
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| Solution | Bractals | 2014-01-23 05:08:06 |
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