(In reply to
re(4): Argand  grand! by Harry)
Construct ray AP' such that /BAP' = /FAC.Construct ray BP" such that /ABP" = /AFC.
P is the intersection of AP' and BP".
More detail on "Construct ray BP" such that /ABP" = /AFC".
1) If any of the rays BA, FA, or FC are too short you should extend them.
2) Construct circle(F,r) intersecting FA at K and FC at L.
3) Construct circle(B,r) intersecting BA at I.
4) Construct circle(I,KL) intersecting circle(B,r) at two points and pick one as P" such that /ABP" = /AFC as directed angles.
Note that when constructing the circles that only enough of the circle is needed to define any intersection points.
Hope this helps.

Posted by Bractals
on 20131204 05:14:19 