(In reply to
re(4): Argand - grand! by Harry)
Construct ray AP' such that /BAP' = /FAC.Construct ray BP" such that /ABP" = /AFC.
P is the intersection of AP' and BP".
More detail on "Construct ray BP" such that /ABP" = /AFC".
1) If any of the rays BA, FA, or FC are too short you should extend them.
2) Construct circle(F,r) intersecting FA at K and FC at L.
3) Construct circle(B,r) intersecting BA at I.
4) Construct circle(I,|KL|) intersecting circle(B,r) at two points and pick one as P" such that /ABP" = /AFC as directed angles.
Note that when constructing the circles that only enough of the circle is needed to define any intersection points.
Hope this helps.
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Posted by Bractals
on 2013-12-04 05:14:19 |
re(5): Argand - grand!
