All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
8 Dice II (Posted on 2013-12-03) Difficulty: 3 of 5
Eight standard dice are arranged to form one larger die with twice the linear size.

Just as in ordinary dice, the opposite faces of the larger die add up to some constant value, though of course larger than the standard 7.

Three of the faces of the large die each have a perfect square number of pips and three have a prime number of pips each. No two faces of the large die have the same number of pips.

There are several ways of accomplishing the above, but only one uses no 4's from the original smaller dice. What is the arrangement of the smaller dice that keeps all their 4-pip faces hidden while forming a larger die that meets the criteria of the first three paragraphs?


From Enigma No. 1768, "Die hard", by Susan Denham, New Scientist, 28 September 2013, page 32.

No Solution Yet Submitted by Charlie    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
There are no comments yet.
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (10)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information