All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
A Quicky III (Posted on 2014-04-09) Difficulty: 1 of 5
If each of the a,b,c,d is a decimal digit - for how many ordered quadruplets (a,b,c,d) is the sum S= a+b+6c+d divisible by 3 ?

Answer: within 20 sec.

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: How many are divisible by 1? | Comment 5 of 9 |
(In reply to How many are divisible by 1? by Steve Herman)

My understanding of "ordered quadruplets" is that (1,1,1,2) differs from (1,2,1,1), etc., and each counts as a separate ordered quadruplet.
  Posted by Charlie on 2014-04-09 12:46:01

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information