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8675309 (Posted on 2014-02-26) Difficulty: 3 of 5
Jenny's phone number is 867-5309, according to the song. Here are some problems about the number 8675309.

1. 8675309 is prime. How many prime phone numbers are there if phone numbers are 7 digits and cannot start with 0?

2. How many prime phone numbers are there if phone numbers are 7 digits and can start with 0?

3. 8675309 is the 582161st prime, and 582161 is prime, too. Therefore, 8675309 is a superprime. How many superprimes are ≤8675309?

4. 8675311 is prime. Therefore, 8675309 and 8675311 are twin primes. How many twin prime pairs (n, n+2) are there such that n≤8675309?

See The Solution Submitted by Math Man    
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Solution computer solution Comment 2 of 2 |

I could have sworn that when this was in the queue a combined 3 and 4 was asked for also: a count of superprimes that are also the bottom prime of a twin.  In any case, I've included that here also.

   10   P=1
   20   while P<9999999
   30    P=nxtprm(P)
   40    inc Ct
   50    if P>1000000 then inc Ct7d
   60    if prmdiv(Ct)=Ct and P<=8675309 then inc Supct
   70    if prmdiv(P+2)=P+2 and P<=8675309 then inc Twinct
   80    if prmdiv(Ct)=Ct and prmdiv(P+2)=P+2 and P<=8675309 then inc Suptwinct
  150   wend
  160   print Ct-1,Ct7d-1,Supct,Twinct,Suptwinct

 664579          586081          47753   52196   4281

664579 primes of up to 7 digits (puzzle part 2),
586081 primes with exactly 7 digits (part 1),
47753 superprimes in the given range,
52196 twin prime pairs,
4281 twin prime pairs where the lower number is a superprime.

BTW, adding line

90    if prmdiv(Ct)=Ct and prmdiv(P-2)=P-2 and P<=8675309 then inc Suptwinct2

finds that 4431 superprimes in the range are the upper number in a twin prime pair.

in fact

  100    if prmdiv(Ct)=Ct and prmdiv(P-2)=P-2 and prmdiv(P+2)=P+2 and P<=8675309 then inc Suptwinct3
finds that in two cases a superprime was between two other primes.  Actually however there's only one such case: 5: it's the 3rd prime and both 2 and 7 are also prime. The code erroneously counted 3, as the 2nd prime (ok), but it counted 1 as being prime, due to the nature of the UBASIC interpreter giveing 1 as the lowest prime factor of 1. This also affects the count of twin prime pairs where the upper number is a superprime, as it would look at 1 (as that would be p-2) also and declare it prime, so that count should be 4430 rather than 4431.


And, I see from tomarken's comment that the super prime count itself, 47753 above, is also off by 1.  I see now that this is the result of 2 being counted, as it is the 1st prime and the software is again counting 1 as prime.


  Posted by Charlie on 2014-02-26 17:07:50
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