Consider a right triangle ABC and construct a point P inside the triangle such that the angles PBC, PCA and PAB are equal.

*** Adapted from a problem which appeared in a Hungarian Math Contest..

(In reply to re: Solution by Bractals)

Me, too.

 A minor remark: in a  right angle triangle ABC it is customary that the angle ACB is the right angle and the opposite side is labeled c,  so that a^2+b^2=c^2  as  we all are used to.

Posted by Ady TZIDON on 2015-02-26 09:21:13