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More randomness! (Posted on 2003-06-30) Difficulty: 3 of 5
Suppose you have a function (or a magic ball) that is capable of producing a totally random integer between 1 and 5 (inclusive).

Using this, how would you generate a random number (also an integer) between 1 and 7 (inclusive)? (Note that the for the number to be random, all integers between 1 and 7 must have an equal chance of being generated)

Assume that using your 1-5 generator is pretty time-consuming, so you want to minimize the number of times you are going to use it.

See The Solution Submitted by levik    
Rating: 4.3333 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Quick and Dirty Solution | Comment 5 of 16 |
(In reply to Quick and Dirty Solution by friedlinguini)

Where you say
int result = (c % 3) + 1;
I assume you mean 7 rather than 3, but then I don't see the reason for checking that it's less than or equal to 7.

Under this assumption, however, while c can be anything from 0 to 24, when taken mod 7, zero through three will come up more often than four through six (on a 4-to-3 ratio) as 0-6 is one complete set; 7-13 is another; 14-20 another, but 21-24 are an incomplete set, re-representing what are now overrepresented digits.
  Posted by Charlie on 2003-06-30 08:50:42

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