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Equal differences (Posted on 2015-08-23) Difficulty: 4 of 5
Given the positive integers, x, y, and z, are consecutive terms of an arithmetic progression, the least value of the positive integer, n,
for which the equation, x^2 – y^2 – z^2 = n, has exactly two solutions is n=27
since 34^2 – 27^2 – 20^2 = 27
and 12^2 – 9^2 – 6^2 = 27.
It turns out that n=1155 is the least value for which there are exactly ten solutions.

How many values of n less than one million have exactly ten distinct solutions?
Source: Project Euler

No Solution Yet Submitted by Ady TZIDON    
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  Subject Author Date
a startxdog2015-08-24 12:15:16
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