All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Equal differences (Posted on 2015-08-23) Difficulty: 4 of 5
Given the positive integers, x, y, and z, are consecutive terms of an arithmetic progression, the least value of the positive integer, n,
for which the equation, x^2 – y^2 – z^2 = n, has exactly two solutions is n=27
since 34^2 – 27^2 – 20^2 = 27
and 12^2 – 9^2 – 6^2 = 27.
It turns out that n=1155 is the least value for which there are exactly ten solutions.

How many values of n less than one million have exactly ten distinct solutions?
Source: Project Euler

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
a startxdog2015-08-24 12:15:16
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (1)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information