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It has become obvious that the Shapes category was in way over its head with all sorts of geometrical problems. So, the hard-core Geometry problems will now reside here, where they will fit in much better.
In right angled ΔABC, ∠ABC=90 and ∠BCA=60. The incircle of ΔABC touches sides BC and AB at points D and E respectively. Let F be the midpoint of DE. P, Q, R are the feet of perpendiculars from F on BC, CA, AB respectively.

Find (AB+BC+CA)/(PQ+QR+RP).
(No Solution Yet, 1 Comments) Submitted on 2019-04-13 by Danish Ahmed Khan   
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