Problem (1):
I have some pencils and some jars.
If I put 4 pencils into each jar I will have one jar left over.
If I put 3 pencils into each jar I will have one pencil left over.
How many pencils and how many jars?

Problem (2):
Again I have some pencils and some jars.
If I put 9 pencils into each jar I will have two jars left over.
If I put 6 pencils into each jar I will have three pencils left over.
How many pencils and how many jars?

Woohoo,
SK made one so easy even the Fatboy can do it:

For problem one,
setting x equal to the number of jars and y equal to the number of pencils we find:
3x+1 = y and
4(x-1) = y
two equations, two unknowns x = 5jars and y equals 16 pencils

for number two:
6x + 3 = y and
9(x-2) = y

so x = 7 jars and y = 45 pencils ...

Now the rest of you can point out what I missed... there must be something

Posted by FatBoy on 2003-12-16 08:34:03