Suppose ABC is an equilateral triangle and P is a point inside the triangle, such that PA = 3 cms., PB = 4 cms., and PC = 5 cms.
Then find the length of the side of the equilateral triangle.

(In reply to a solution? by Rachel)

Rachel, It looks like lines of length 4 should be close to meeting,but 8[3^1/2] is nearly 14 - do you mean 4[3^1/2] ?

Posted by Jils on 2003-12-18 11:29:39