A dealer offers to you to play a game. He shows you three two-sided cards: one with both sides red, one red and black and the other black and black. He puts them in a hat, and randomly (no tricks here) takes out a card and puts it on the table.
You both see only one side of the card. At this point he says that if the bottom side is the same as the top, he will take your money. If the other side is different, you double it. He explains that by now one of the cards is ruled out - if you're seeing red, the card cannot be a double black card, and vise versa - so you have a 50/50 chance of winning.
Is this a fair game? Why or why not?
There are 6 card sides you can see. 3 back and 3 red. Of thoughs 6 possiblities there are 4 loosing combonations and 2 winning combonations. A 1 in 3 chance of winning. Once you see the color there are 2 cards with 4 sides. You know one side of one card so there are 3 hidden sides. Only 1 of the 3 hidden sides will make you win. It is still a 1 in 3 chance of winning.
This is a very bad bet!
seems simple to me
