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3 cards (Posted on 2002-05-11) Difficulty: 3 of 5
A dealer offers to you to play a game. He shows you three two-sided cards: one with both sides red, one red and black and the other black and black. He puts them in a hat, and randomly (no tricks here) takes out a card and puts it on the table.

You both see only one side of the card. At this point he says that if the bottom side is the same as the top, he will take your money. If the other side is different, you double it. He explains that by now one of the cards is ruled out - if you're seeing red, the card cannot be a double black card, and vise versa - so you have a 50/50 chance of winning.

Is this a fair game? Why or why not?

See The Solution Submitted by levik    
Rating: 3.5385 (13 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
OddsRandyOrton2004-10-21 15:14:57
seems simple to meDan Porter2004-01-20 11:07:00
A-priori probabilityAndy2003-11-20 11:22:59
I agree with the solutionS2003-10-30 23:24:03
ideajen2003-10-29 18:11:04
re: Clarified explanation (solution)Gamer2003-07-14 17:08:00
No Subjectmolly2003-06-11 17:53:58
Clarified explanation (solution)Ryan2003-05-07 07:22:41
no fairMel2002-08-23 03:44:27
re(3): Simply stated (solution)levik2002-07-16 08:40:34
Solutionre(2): Simply stated (solution)TomM2002-07-16 00:56:54
re: Simply stated (solution)levik2002-07-15 18:22:02
Some ThoughtsSimply stated (solution)Henry2002-07-15 09:58:05
solution?marty2002-05-22 22:44:06
blehTom Bayer2002-05-13 21:36:45
1/3Michael2002-05-12 19:18:31
The choicesDavid2002-05-12 09:33:08
Hints/TipsMy thoughtsTomM2002-05-11 07:15:40
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