There is a small town situated by a barbarian colony. The population in this town is very small, but they live well. Upon seeing the villagers in this town so happy, a group of thirty two barbarians sneak up and position themselves around the city. All the barbarians fired at exactly the same time, and every bullet went over 3 villager's heads before it killed another person, including anyone who may have been shot already. If no villager was at the same place at the time (and all villagers were in the town) when the simultaneous shooting occurred, what is the fewest amount of villagers in the town? (Note: "Around" means actually around. A line going around the city would work, but one going out of the city would not.)

(In reply to Barbarians at the gates !! by Penny)

This is clearly not the solution Gamer was looking for. He wants a complex math solution involving a circle with 32 intersecting lines crossing it. He should have specified that each bullet goes over three VILLAGER'S heads, and also that each of the barbarians fires INTO the village. Little loopholes... But at least I spared all the villagers.

:-)

Posted by Penny on 2004-01-28 16:42:15