There is a small town situated by a barbarian colony. The population in this town is very small, but they live well. Upon seeing the villagers in this town so happy, a group of thirty two barbarians sneak up and position themselves around the city. All the barbarians fired at exactly the same time, and every bullet went over 3 villager's heads before it killed another person, including anyone who may have been shot already. If no villager was at the same place at the time (and all villagers were in the town) when the simultaneous shooting occurred, what is the fewest amount of villagers in the town?
(Note: "Around" means actually around. A line going around the city would work, but one going out of the city would not.)
With the assumption that barbarians are NOT killing other barbarians... and that everyone must be shot only once... (meaning, as e.g. mentioned earlier, that it must be AT LEAST 32)...
The answer is 32. I'm trying to put together a text picture that will exemplify this... but it's not easy. I'll post when I have it ready.
Solution
