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Just Math
trigonometry and a triangle (
Posted on 2004-02-26
)
Prove that in a triangle ABC,:
sin(A)sin(B)sin(C) + cos(A)cos(B) = 1
implies:
A = B = 45° and C = 90°.
See The Solution
Submitted by
mohan
Rating:
2.7143
(7 votes)
Comments: (
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lol
| Comment 8 of 15 |
lol i dont know what this problem is about, but it has probly been used before. It is hard to think of mew, original problems like that when there are already so many out there.
Posted by
matt runchey
on 2004-02-27 17:36:49
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