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e, i, and π (Posted on 2004-03-02)

i² = -1
e^(i π) = -1

(-e)^(i π) = ?

Simplify to a number without i. Leave e and π in their symbol forms.

See The Solution Submitted by Tristan

Rating: 2.8571 (7 votes)

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solution

| Comment 1 of 12

(-e)^(iπ) = ((-1)e)^(iπ) = (-1)^(iπ) * e^(iπ) = (e^(iπ))^(iπ) * (-1) = e^(i²π²) * (-1) = e^(-π²) * (-1) = - e^(-π²)

That comes out to about -0.0000517231862.

Posted by Charlie on 2004-03-02 09:08:39

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