Find a 3x3 magic square that is composed of 9 prime numbers (not the numbers from 1-9) and show how you found it.

(A magic square, as you may already know, is one in which the respective sums of the numbers in all the rows, columns, and both major diagonals all add up to the same number.)
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Since "Magic Square" is a term used outside the scope of this problem, I'm sure you can find an answer on the internet. Please find a solution independently.

(In reply to re: lower square - failure by Tristan)

to give a form let our magic square look like this:

(x-a)  (x+d)  (x+c)

(x+b) (  x  )  (x-b)

(x-c)  (x-d)  (x+a)

Without loss of generality, all variables in this case can be considered positive.

comparing sums of opposite columns teaches us that b=a+c

comparing sums of top and bottom rows teaches a=c+d

and likewise b=2c+d

Posted by Eric on 2004-03-09 21:23:50