The pictured tetrahedron has four identical rectangular (i.e., right-angled or pythagorean) triangles as faces, with

AB=CD=p,
AC=BD=q,
AD=BC=r,
and p²+q²=r².

What's its volume, as a function of p, q and r?

Make rectangle ABCD, this satifies the conditions. The 'volume' is zero.

On cannot "stretch" this rectangle into 3-dimensions without altering either the angles or the sides.

-Jer

Posted by Jer on 2004-04-26 12:11:38