Fill a 3x3 square with the numbers from 1 to 9, so the four sides and the two diagonals share the same sum, which is to be as large as possible.
There are only three really unique squares that meet the conditions of the puzzle:
sum=12
1 8 3
9 7 5
2 6 4
sum=15
2 7 6
9 5 1
4 3 8
sum=18
6 4 8
5 3 1
7 2 9
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Posted by Penny
on 2004-06-22 11:54:15 |