All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > General
More or less magic square (Posted on 2004-06-22) Difficulty: 3 of 5
Fill a 3x3 square with the numbers from 1 to 9, so the four sides and the two diagonals share the same sum, which is to be as large as possible.

See The Solution Submitted by Federico Kereki    
Rating: 3.2500 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Three distinct squares | Comment 3 of 11 |
There are only three really unique squares that meet the conditions of the puzzle:
 
sum=12
1 8 3         
9 7 5     
2 6 4    
 
sum=15
2 7 6
9 5 1
4 3 8
 
sum=18
6 4 8
5 3 1
7 2 9

  Posted by Penny on 2004-06-22 11:54:15
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (5)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (7)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information