All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Multiplying gets a square? (Posted on 2004-06-26) Difficulty: 3 of 5
Is it possible to get a perfect square if you multiply three consecutive natural numbers?

See The Solution Submitted by Federico Kereki    
Rating: 3.0000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 7 of 25 |

Consider (x - 1)x(x + 1) = x(x² - 1) = y².

Since the greatest common divisor of x and x² - 1 is 1, we have x = a², x² - 1 = b², for some natural numbers a and b.

But then (a²)² - b² = 1, which is impossible if a² and b are natural numbers.

Hence the product of three consecutive natural numbers cannot be a perfect square.

As a generalization, the product of any number of consecutive positive integers is never a perfect power.  This was proved by Erdös and Selfridge in 1975.


  Posted by Nick Hobson on 2004-06-26 13:31:01
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information