I thought of three numbers.
Their sum is 6.
The sum of their squares is 8.
The sum of their cubes is 5.
What is the sum of their fourth powers?
According to linear programming and combinatorial optimization, the problem has no solution in the real domain.
I *THINK* the answer is 0 but I have no method with which to prove it.
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Posted by Eric
on 2004-07-01 10:22:52 |