I thought of three numbers.
Their sum is 6.
The sum of their squares is 8.
The sum of their cubes is 5.
What is the sum of their fourth powers?

(In reply to Solution by np_rt)

I just noticed that I made a mistake. At the very bottom, I wrote a^4+b^4+c^4+2a^2*b^2+2a^2*c^2+2b^2*c^2=64. When I plugged in 32 for that expression, I forgot to include that factor of 2.

After the correction, the solution is 0!

Posted by np_rt on 2004-07-01 15:11:10