A man had a 10-gallon keg full of wine, and an empty jug. On Monday he drew off a jugful of wine and filled up the keg with water. On Friday, after the wine and water had been thorougly mixed, he drew off another jugful and again filled up the keg with water. The keg then contained equal quantities of wine and water.

What was the capacity of the jug?

i may have used an awkward method. i thought of the wine left after the first pour as X tenths. i wanted X such that when X tenths is squared it results in 5 tenths.
that makes X equal to the square root of 50. so number of gallons the jug holds is 10 minus the square root of 50.

my calculator reads: 2.928933

Posted by rixar on 2004-07-14 19:59:47