A man had a 10-gallon keg full of wine, and an empty jug. On Monday he drew off a jugful of wine and filled up the keg with water. On Friday, after the wine and water had been thorougly mixed, he drew off another jugful and again filled up the keg with water. The keg then contained equal quantities of wine and water.
What was the capacity of the jug?
(In reply to
re: the CORRECT solution by rixar)
thinking...
Edited on July 14, 2004, 9:32 pm
The simple answer of (1-j/10)^2=50% => j = 2.929 gallon is correct. I just can't see why my original (overly complicated) method is wrong :-/
Edited on July 14, 2004, 10:32 pm
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Posted by David
on 2004-07-14 21:19:08 |
re(2): the CORRECT solution
