A man had a 10-gallon keg full of wine, and an empty jug. On Monday he drew off a jugful of wine and filled up the keg with water. On Friday, after the wine and water had been thorougly mixed, he drew off another jugful and again filled up the keg with water. The keg then contained equal quantities of wine and water.
What was the capacity of the jug?
Hi
I am new to this group, when I read the Keg of wine problem I answered as follows:
On Monday 1 jug is removed and replaced with water.
On Friday, after thorough mixing, a jug is removed. This jug contains 50% wine and 50% water (thorough mixing) and is replaced by water.
So now the keg contains 1.5 Jugs of water and the rest wine.
But we are told that the keg is now 50/50 wine water so 1.5 jugs is half the keg (10 gallons)
1.5J = 5
J = 10/3 = 3.33 Gallons
This seems to differ from the other answers, what am I missing?
David
Different Solution - Where Am I going wrong?
