Do the three hands on an analog clock (hours, minutes, seconds) ever divide the face of the clock into three equal segments, i.e. 120 degrees between each hand?

(In reply to re(3): Solution by Charlie)

If the second hand is only 33 degrees from the minute hand, it does not fit the requirements asked for - ALL 3 HANDS 120 DEGREES FROM EACH OTHER.

At about 12:43.383, the hour hand is 3/5 the way to the 1 (minute 3), the minute hand is 2/5 the way between the 8 and 9(minute 43). This puts the minute hand and hour hand 120 degrees apart. So the exact point for the second hand would have to be across from the halfway point of these two (minute 53), which is 23 seconds, not 38 seconds.

You're 15 seconds too late.

EDIT - oops, thats 3/5 for the minute hand. Also, the second hand is 3/5 the way from the 4 and 5.

Edited on July 20, 2004, 4:12 pm

Posted by Jim on 2004-07-20 16:10:58