A round hole is drilled through the center of a spherical solid with a radius (r). The resulting cylindrical hole has height 4 cm.
a)What is the volume of the solid that remains?
b)What is unusual about the answer?
a) If a is the radius of the drilled hole, then r^2 = a^2 + 2^2. If we let a -> 0, then r -> 2. Therefore, the volume of solid that remains is (4/3)*ð*r^3 or 32*ð/3 cm^3.
b) The answer is independent of the radius r. Although r must be greater than 2.
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Posted by Bractals
on 2004-08-21 10:00:48 |
Clever problem.
