Triangle ABC has side AB=AC, and angle BAC = 20 degrees.
D is a point on side AC with AD=BC. Find angle DBC.
Solve this without trigonometry.
(In reply to
re(2): Solution by cheating by Ken Haley)
Exactly, I didn't prove that... that's where I cheated. If you look at a problem called "Measure That Angle" (no II or III) you'll see that for a 20 degree isosceles triangle, you will have AD = DE = EB = BC.
I didn't prove it, I cheated and used prior knowledge.
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Posted by nikki
on 2004-09-09 08:26:03 |