A round hole is drilled through the center of a spherical solid with a radius (r). The resulting cylindrical hole has height 4 cm.

a)What is the volume of the solid that remains?

b)What is unusual about the answer?

Vol of sphere = 4/3*pi*2^3.

We assume the radius of sphere to be 2 because the hole drilled has a height of 4 which should equal 2r.

Vol of sphere = 32/3*pi

Vol of cylinder = pi*r^2*4 = 4*pi*r^2.

Volume remaining = 32pi/3 - 4pi*r^2

b). The answer will be ununusual since we can't take into consideration the curvature at the top of the sphere which doesn't account for the radius of the drilled cylindrical hole.

Posted by Osi on 2004-11-05 09:36:31