Given that 38! = 523,022,617,466,601,111,760,007,224,100,abc,def,gh0,000,000, determine, with a minimum of arithmetical effort, the digits a, b, c, d, e, f, g, and h. No calculators or computers allowed!

I have a meeting in 5 minutes, but I can say that 38! ends in 8 zeroes.  1 for each of 5, 10, 15, 20, 30 and 35 plus 2 for 25.  (There are plenty of 2's to go around)

So h=0

and g<>0 (I think <> means 'is not equal to')

-Jer

Posted by Jer on 2004-11-10 14:22:24