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| Missing Digits (Posted on 2004-11-10) |
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Given that 38! = 523,022,617,466,601,111,760,007,224,100,abc,def,gh0,000,000, determine, with a minimum of arithmetical effort, the digits a, b, c, d, e, f, g, and h. No calculators or computers allowed!
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No Solution Yet
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Submitted by Nick Hobson
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Rating: 2.8000 (5 votes)
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re: Until I have time
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 | Comment 2 of 8 | 
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(In reply to Until I have time by Jer)
Agreed. And as the product of the digits 1-4 & 6-9 ends in 6, and 1-4 & 6-8 ends in 4....6*6*6*4 gives a 4 for "g"
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Posted by Nosher
on 2004-11-10 18:48:01 |
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