Find a solution to:
x
1^4 + x
2^4 + x
3^4 + ... + x
n^4 = 1999
where each xy is a distinct integer.
(Or prove that it is impossible).
Since any X integer raised to the 4th power yields a positive number, X<=6 because X> 6 yields values higher than 1999.
So, -6<= X <=6, or we can use the X =1, to X=6 values twice and still have a distintive integer.
A quick check of these, and one can see that 2004 has distintive X solution, but not 1999.
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Posted by Michael
on 2004-11-26 21:01:03 |