The following long division problem is not correct. In fact, none of the digits is what it should be.

Change each of the digits to a different digit so that the arithmetic is correct.

Note that there is no remainder, no leading zeroes, and like digits are not necessarily all changed to the same digit.

The first thing I found is that the leading 4 in the quotient must be a 1, 2, or 3. The minimum that the divisor can be is 20. And since that leading digit in the quotient times the divisor is a 2 digit number, it must be less than 5. Since it can't be 4, it must be 1, 2, or 3.

And since the divisor is at least 20, the dividend must be at least 20*1000=20000.

Also, that 3 in the 365 must be a 1. Also, the 3 in the 4321 must be a 0.

That's all I got so far. Will work on it a bit more.

Edited on December 3, 2004, 5:56 pm

Edited on December 3, 2004, 6:01 pm

Posted by np_rt on 2004-12-03 17:54:26