A rope with its two ends held in place forms a curve called a catenary (assuming that the stiffness of the rope is negligible). A catenary takes the shape of the function:
f(
x) =
a cosh(
x/
a),
where cosh is the hyperbolic cosine function.
If a 50-foot rope hangs by its ends from two flagpoles, one 50 feet tall and one 40 feet tall, and at its lowest point is 20 feet above the ground, how far apart are the flagpoles?
(In reply to
Solution by np_rt)
Well, FL, it looks like at least one person fell in your little trap and used math instead of common sense.
Sorry, np_rt, Re-read the numbers given. How far down does the rope have to hang?
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Posted by TomM
on 2002-12-25 02:59:07 |