All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > General
Buric's Cube (Posted on 2004-12-22) Difficulty: 4 of 5
Professor Buric likes to set his students logic problems using eight normal dice in a 2󫎾 cube as shown here.

Let the six faces of the cube be referred to as:

ABFE - TOP
ABCD - FRONT
DCGH - BASE
EFGH - BACK
AEHD - LEFT
BFGC - RIGHT
Each of the six faces shows four numbers and three faces of one die are seen at each of the eight corners of the cube. The Professor then makes several statements regarding the viewable numbers and challenges the students to place all twenty four visible numbers in their correct positions in 40 minutes or less.

On one occasion the following clues were given:

  1. All six faces show four different numbers but each of the numbers 1, 2, 3, 4, 5, and 6 appear four times.
  2. The numbers on the front can be arranged to make a four-digit square number, and those on the back can form a different four-digit square.
  3. The sum of the numbers showing on the top is the same total as those on the base.
  4. The numbers showing at corner F are 2, 3, and 6.
  5. The numbers seen on the front are consecutive, but not necessarily in order.
  6. Three odd numbers form corner B, and the product of all the numbers on the top is 180.
  7. At corner G, the sum of the numbers is only 7, while at corner E, only even numbers are seen, and each of these is either the largest or smallest number seen on its face.
  8. The numbers on the right side do not include a 6, and only one 5 appears in the top half of the cube.
  9. At corner C, one of the numbers equals the sum of the other two.
Knowing that the dice need not be identical, as the only rule governing the positions of the numbers on these dice is that opposite faces add up to seven, can you graduate from the Professor's class?

No Solution Yet Submitted by SilverKnight    
Rating: 4.2222 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Failed - darned clue 7 | Comment 5 of 7 |

I would have failed this problem based on the time requirement.  I got messed up because I misunderstood clue 7, and it delayed my answer. I thought the "each of these is either the largest or smallest number seen on it抯 face" referred to both dice E and G, not E alone.  Did anyone else get sidetracked by this?

But I eventually found the answer.  I would have posted it, but it was all in paragraph explanation form.  DJ's explanation with his chart was much clearer than mine, so I won't post it even for the "if your brain looks at things differently, this approach might appeal to you" reason.


  Posted by nikki on 2004-12-28 16:28:44
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information