All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Remainder of One (Posted on 2004-12-29) Difficulty: 4 of 5
Let p be a prime. Let S be a set of (p-1) integers, none of which are divisible by p. Show that some subset of S has a sum that has a remainder of 1 when divided by p.

(The sum of a set is defined as the sum of the elements of the set)

See The Solution Submitted by David Shin    
Rating: 3.8750 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: p <= 5 and more | Comment 7 of 13 |
(In reply to p <= 5 and more by Richard)

I think that you can even eliminate 1 from the set of remainders and just need to show that with the p-1 numbers drawn from {2,...,p-1} you can achieve a sum equal to 1 mod p.

Other than that observation I have nothing to offer. 


  Posted by ken on 2005-01-02 00:26:14
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information