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String length differences (Posted on 2005-02-15) Difficulty: 3 of 5
Consider the sequence 0100111100
There are 5 zeroes and 5 ones in this sequence.
The longest string of ones is 4.
The longest string of zeroes is 2.
The difference in string lengths is 2.

Create a sequence consisting of 100 zeroes and 100 ones which maximizes the difference in lengths between the longest string of 1's and the longest string of 0's.

Find a formula for the maximum difference in string lengths with n zeroes and n ones.

See The Solution Submitted by Jer    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution to part 1 | Comment 2 of 5 |
The solution seems to be
n 0's + k 1's + n 0's + 1 1 + n0's + 1 1 + ... + 1 1 + n 0's
where the last group with be short a few 0's

the number of 0 groups = ceil(100/n)
the number of single 1's = ceil(100/n) - 2
k = 102 - ceil(100/n)

Per excel, k - n is maximum of 82 when k = 10 and n = 92

A solution is
10 0's +
92 1's +
10 0's +
  1 1   +
10 0's +
  1 1   +
10 0's +
  1 1   +
10 0's +
  1 1   +
10 0's +
  1 1   +
10 0's +
  1 1   +
10 0's +
  1 1   +
10 0's +
  1 1   +
10 0's




  Posted by Steve Herman on 2005-02-15 15:27:17
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