All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Even and odd powers (Posted on 2005-02-09) Difficulty: 4 of 5
Let [z] mean the Greatest Integer less than or equal to z. Find a positive real number X, such that [X^n] is an even number whenever n is even, and [X^n] is an odd number whenever n is odd.

See The Solution Submitted by SteveH    
Rating: 4.2222 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
No Subject | Comment 5 of 23 |

Shin's solution may be wrong.  With X=1+sqr(3), [X]=2, [X^2]=4, [X^3]=6, etc.

If n is assumed to start with n=1, then X=-.5 (or any number between -1 and 0) works.  [X]=0, [X]=-1, [X^2]=0, [X^3]=-1, etc.  In general [X^n]=0 when n is a positive even integer and [X^n]=-1 when n is an odd positive integer.


  Posted by McWorter on 2005-02-25 23:10:46
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information