Let [z] mean the Greatest Integer less than or equal to z. Find a positive real number X, such that [X^n] is an even number whenever n is even, and [X^n] is an odd number whenever n is odd.

(In reply to re: No Subject by David Shin)

My mistake.  You are so right.  Your solution is also correct.  Although I don't see the point of sqr(3).  sqr(2) works just as well.  Or even X=k^2+sqr(k^2+m), where k is any positive integer and m is a positive integer less than 2k+1; right?  (Hope this isn't my third mistake!)

Posted by McWorter on 2005-02-27 00:02:31