Prove that if a right triangle has all sides of integral length, then it has at most one angle bisector of integral length.
I was thinking it said there was a guarantee that exaclty one bisector would be integral. The problem is to prove there cannot be MORE than one. Whoops.
I don't have time to finish this, but feel free to use my results as a starting point.
|
Posted by Jer
on 2005-03-04 18:52:45 |